Bicol University
College of Education
Integrated laboratory High School
BIOLOGY
Name_________________________ Section______ Date_______ Score______
Directions:
Read the following statements carefully. Shade the letters of the correct answer.
1. The strands of the DNA double helix are held together A B C D
by pairing of _________.
A. Sugars C. Phosphates
B. Nitrogen bases D. Nucleotides O O O O
2. ____________ are monomers that make up the DNA.
A. Nucleic acid C. amino acids
B. Peptides D. nucleotides O O O O
3. The nitrogenous base which is NOT present in DNA
is _________.
A. Adenine C. Thymine
B. Uracil D. Cytosine O O O O
4. The following statements are INCORRECT except
A. The sugar in DNA is ribose.
B. The base pair is not complementary.
C. The pairs of nucleotides ca appear in any order.
D. The DNA is found on the cytoplasm of the cell. O O O O
5. Rosalind Franklin discover the helix shape of the DNA
by __________.
A. comparing nucleotides C. using enzymes
B. x-ray diffraction D. counting bases O O O O
6. Who was/were the scientist/s who developed a model
of a DNA using tins and wires and found out that DNA
has a double helix shaped?
A. Oswald Avery C. James Watson & Francis Crick
B. Frederick Griffith D. Martha Chase & Alfred Hershey 6 O O O O
7. What are the two common parts of a DNA nucleotide?
A. sugar & phosphate C. phosphate & base
B. sugar & base D. purines & pyrimidines O O O O
8. __________ made a key discovery regarding the chemical
structure of a DNA.
A. Oswald Avery C. Frederick Griffith
B. Erwin Chargaff D. James Watson O O O O
9. In the ladder model of DNA, what represents the uprights
and rungs of the ladder?
A. Uprights: deoxyribose & phosphate; Rungs: nitrogen base
B. Uprights: nitrogen base; Rungs: deoxyribose & phosphate
C. Uprights: nitrogen base; Rungs: ribose & phosphate
D. Uprights: ribose & phosphate; Rungs: nitrogen base O O O O
10. Purines is to adenine & __________ where as pyrimidines
is to __________ & cytosine.
A. thymine : guanine C.guanine : thymine
B. uracil : thymine D. uracil : guanine O O O O
11. Which of the following statement is CORRECT?
A. Pyrimidines can only be pairs with pyrimidines.
B. Adenine can only be pairs with guanine.
C. Purines pairs only with purines.
D. Cytosine can only be pairs with guanine. O O O O
In pea plants, spherical seeds (S) are dominant to dented seeds (s). In a genetic cross of two plants that are heterozygous for the seed shape trait, what fraction of the offspring should have spherical seeds?
A. None O O O O
B. ¼
C. ½
D. 3/4
12. Aphenotypic ratio of 3:1 in the offspring of a mating of two organisms heterozygous for a single trait is expected when:
A. the alleles segregate during meiosis.
B. each allele contains two mutations. O O O O
C. the alleles are identical.
D. the alleles are incompletely dominant.
E. only recessive traits are scored.
14. In Mendel's "Experiment 1," true-breeding pea plants with spherical seeds were crossed with true-breeding plants with dented seeds. (Spherical seeds are the dominant characteristic.) Mendel collected the seeds from this cross, grew F1-generation plants, let them self-pollinate to form a second generation, and analyzed the seeds of the resulting F2 generation. The results that he obtained, and that you would predict for this experiment are: O O O O
A. 1/2 the F1 and 3/4 of the F2 generation seeds were spherical.
B. 1/2 the F1 and 1/4 of the F2 generation seeds were dented.
C. All of the F1 and F2 generation seeds were spherical.
D. All the F1 and 3/4 of the F2 generation seeds were spherical.
13. A genetic cross between two F1-hybrid pea plants for spherical seeds will yield what percent spherical-seeded plants in the F2 generation? (Recall, spherical-shaped seeds are dominant over dented seeds.)
A. 100%
B. 75% . O O O O
C. 50%
D. 25%
15. A genetic cross between two F1-hybrid pea plants having yellow seeds will yield what percent green-seeded plants in the F2 generation? Yellow seeds are dominant to green.
A. 0%
B. 25%
C. 50% O O O O
D. 75%
16.When true-breeding tall stem pea plants are crossed with true-breeding short stem pea plants, all of the _________ plants, and 3/4 of the __________ plants had tall stems. Therefore, tall stems are dominant.
A. F1, F2.
B. G1, G2. O O O O
C. parental, F2.
D. F2, parental.
17. To identify the genotype of yellow-seeded pea plants as either homozygous dominant (YY) or heterozygous (Yy), you could do a test cross with plants of genotype _______.
A. y
B. Y
C. yy
D. YY O O O O
18. A test cross is used to determine if the genotype of a plant with the dominant phenotype is homozygous or heterozygous. If the unknown is homozygous, all of the offspring of the test cross have the __________ phenotype. If the unknown is heterozygous, half of the offspring will have the __________ phenotype.
A. dominant, incompletely dominant
B. recessive, dominant
C. dominant, epistatic
D. dominant, recessive O O O O
19. In Mendel's experiments, if the gene for tall (T) plants was incompletely dominant over the gene for short (t) plants, what would be the result of crossing two Tt plants?
A. 1/4 would be tall; 1/2 intermediate height; 1/4 short
B. 1/2 would be tall; 1/4 intermediate height; 1/4 short.
C. 1/4 would be tall; 1/4 intermediate height; 1/2 short.
D. All the offspring would be tall. O O O O
A. pink flower color is epistatic to red flower color. O O O O
B. pink flowers are the result of a blending of the red and white genotypes.
C. flower color is due to 2 or more complementary genes.
D. heterozygous plants have a different phenotype than either inbred parent
20. A genetic cross of inbred snapdragons with red flowers with inbred snapdragons with white flowers resulted in F1-hybrid offspring that all had pink flowers. When the F1 plants were self-pollinated, the resulting F2-generation plants had a phenotypic ratio of 1 red: 2 pink: 1 white. The most likely explanation is:
Directions: Identify the complementary strand of the following DNA
AUG-CUG-AUG-GAU-GAC-UAG-GAC-CAG-GAU-CGA-AGA- GCA-CCA-UUU
A.UUU-CUG-AUG-CCA-GCA-AGA-CGA-GAU-CAG-GAC-UAG-GAC-GAU-AUG
B. UAC-AAC-UAC-CUA-CUG-ATC-CUG-GUC-CUA-GCU-UCU-GAU-AUG-UUU
C. UAC-GAC-UAC-CUA-CUG-AUC-CUG-GUC-CUA-GCU-UCU-CGU-GGU-AAA
D. NONE OF THE ABOVE, WRITE YOUR ANSWER AT ATHE BACK OF THE ANSWER SHEET O O O O
AUG--CUG-CCA-GCA- -CAG-GAC-UAG-GAC-GAU-AUG-UUU
A.UAC-GUC-AAA-ACG-CAG-GGC-UAG-CCA-AGA-CGA-AAG-UUU
B. UAC-GAC-GGU-CGU-GUC-GUC-CUG-AUC-CUG-CUA-UAC-UUU
C. UAC-CGU-GUC-UUA-GAU-CAG-CAG-GAC-ACU-UCA-GGU-UUG
D. NONE OF THE ABOVE, WRITE YOUR ANSWER AT ATHE BACK OF THE ANSWER SHEET O O O O
AUG-GGC-AAG-GAA-GCA-ACG-GCG-CAG-GAU-GUC-UCG-CUA-UUU
A. UAC-GAC-UAC-CUA-CUG-AUC-CUG-GUC-CUA-GCU-UCU-CGU-AAA
B. UAC-AAC-UAC-CUA-CUG-ATC-CUG-GUC-CUA-GCU-UCU-GAU-AAA
C. UAC-CCG-UUC-CUU-CGU-UGC-CGC-GUC-CUA-CAG-AGC-GAU-AAA
D. NONE OF THE ABOVE, WRITE YOUR ANSWER AT ATHE BACK OF THE ANSWER SHEET O O O O
No comments:
Post a Comment